gnutmeg: (antisocial)
[personal profile] gnutmeg
basic algebra :D

a + b + c = 0
2a - a + 2b - b + 2c - c = 0
2(a + b + c) - 1(a + b + c) = 0
2(a + b + c) = 1(a + b + c)
2 = 1


Prove me wrong, kiddies, prove me wrong.

on 2003-09-26 11:49 am (UTC)
Posted by [identity profile] agenda.livejournal.com
I had to ask smart people, but they explained me and so I KNOW IT I KNOW IT. ithink

on 2003-09-26 12:45 pm (UTC)
Posted by [identity profile] lirimaer.livejournal.com
Do you? Ok. How'm I wrong?

on 2003-09-26 12:49 pm (UTC)
Posted by [identity profile] agenda.livejournal.com
If a+b+c = 0, and in the final step you're dividing both sides by a+b+c, it cannot be done as you cannot divide anything by zero.

Or something. The smart people had it in five minutes.

on 2003-09-26 12:50 pm (UTC)
Posted by [identity profile] lirimaer.livejournal.com
Yup. That's right. *laugh* Good for you~